Jul. 12th, 2006

c9: (Towel)
I am so awesome. Not really. But I figured out how to do this all by myself:

select i.lastname,i.firstname,count(ic.instructorid) as 'Number of Courses' from instructor as i,instructorcourse as ic where i.type='Facilitator' and i.instructorid = ic.instructorid group by i.lastname,i.firstname

This is primarily for my future reference.
c9: (Default)
Some Etch-A-Sketch pictures I found thanks to [profile] dinosaurcomics. They are totally awesome!

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